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Fix survey-invitations list query to use user.id instead of deprecated user.user_id

Yannick Warnier 7 gadi atpakaļ
vecāks
revīzija
117ff60622
1 mainītis faili ar 1 papildinājumiem un 1 dzēšanām
  1. 1 1
      main/survey/survey_invitation.php

+ 1 - 1
main/survey/survey_invitation.php

@@ -92,7 +92,7 @@ $course_id = api_get_course_int_id();
 $sql = "SELECT survey_invitation.*, user.firstname, user.lastname, user.email
         FROM $table_survey_invitation survey_invitation
         LEFT JOIN $table_user user
-        ON (survey_invitation.user = user.user_id AND survey_invitation.c_id = $course_id)
+        ON (survey_invitation.user = user.id AND survey_invitation.c_id = $course_id)
         WHERE
             survey_invitation.survey_code = '".Database::escape_string($survey_data['code'])."' ";